Given the code fragment: Path file = Paths.get (“courses.txt”); // line n1 Assume the courses.txt is accessible. Which code fragment can be inserted at line n1 to enable the code to print the content of the courses.txt file?

The Files.lines(Path) method reads all lines from a file and returns them as a Stream. This is the most direct and idiomatic way in Java 8 to process a file's content line-by-line using the Stream API. The returned stream can then be consumed by a terminal operation like forEach to print each line. This approach is also memory-efficient for large files as it reads lines lazily.

A. Files.list() is used for listing the contents of a directory, not for reading a file. It would throw a NotDirectoryException at runtime.
B. Files.readAllLines() returns a List, not a Stream. Assigning its result to a Stream variable causes a compilation error.
C. The method call readAllLines(file) is a compilation error. The correct call is Files.readAllLines(file), as it is a static method of the Files class.

- Java SE 8 Platform API Specification, java.nio.file.Files.lines(Path path). The documentation confirms it returns a Stream with the lines from a file.

- Oracle, The Java™ Tutorials, "Reading, Writing, and Creating Files". This tutorial presents Files.lines as the standard method for reading a text file as a stream of lines.