CLSSGB-001 practice question 5 of 30
Due to excessive pollution, GREEN Solutions Inc. is considering subsidizing public transportation to work for its employees. According to the manager…
Full set: 200 questionsTo determine the probability of arriving on time (in 40 minutes or less), we calculate the Z-score for each transportation method, assuming a normal distribution. The Z-score measures how many standard deviations an element is from the mean.
1. Personal Vehicle: Mean (μ) = 39 min, Standard Deviation (σ) = 7 min, Target (X) = 40 min. Z = (X - μ) / σ = (40 - 39) / 7 ≈ 0.143. The probability P(Z ≤ 0.143) is approximately 55.7%.
2. Metro Public Transportation System (MPTS): Mean (μ) = 34 min, Standard Deviation (σ) = 21 min, Target (X) = 40 min. Z = (X - μ) / σ = (40 - 34) / 21 ≈ 0.286. The probability P(Z ≤ 0.286) is approximately 61.3%. Since 61.3% > 55.7%, the probability of arriving on time is higher using the MPTS.
A. The probability for personal vehicles (≈56%) is lower, not higher, than for the MPTS (≈61%).
C. The probabilities are demonstrably different (55.7% vs. 61.3%) and therefore not "about the same."
D. The problem is explicitly about the "average weekday commute," making weekend data irrelevant to the analysis.
E. This statement is a flawed generalization. While the MPTS has a higher standard deviation, its mean is significantly lower, which results in a higher probability of meeting the 40-minute target.
1. Montgomery, D. C. (2013). Introduction to statistical quality control (7th ed.). Wiley. Section 4.3, "The Normal Distribution," explains the use of the standard normal distribution and the Z-score transformation, Z = (X - μ) / σ, to compute probabilities for any normally distributed random variable (pp. 122-125).
2. The Pennsylvania State University. (n.d.). STAT 500: Applied Statistics, Lesson 4: Normal Distribution. Eberly College of Science. Retrieved from https://online.stat.psu.edu/stat500/lesson/4. This courseware details the process of "Standardization" (calculating a Z-score) to find the probability of a value falling within a certain range for any normal distribution.
3. Pyzdek, T., & Keller, P. A. (2018). The Six Sigma handbook (5th ed.). McGraw-Hill Education. Chapter 13, "Basic Control Charts," discusses how the normal distribution is fundamental to understanding process variation and capability, which involves calculating the probability of meeting specifications (pp. 265-267).
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