CLSSGB-001 practice question 5 of 30

Due to excessive pollution, GREEN Solutions Inc. is considering subsidizing public transportation to work for its employees. According to the manager…

Full set: 200 questions
Due to excessive pollution, GREEN Solutions Inc. is considering subsidizing public transportation to work for its employees. According to the manager it takes an average weekday commute of 39 minutes with a Standard Deviation of 7 minutes for the employees to get to work while they use their personal vehicles for their office commute while the management set a policy of not more than 40 minutes for their daily one-way commute. A survey conducted one day on 70 employees showed an average of 34 minutes commuting time using the metro public transportation system with a Standard Deviation of 21 minutes. Assuming a Normal Distribution for the commute times by either personal or public transportation, which of these is true?
Answer options
A: The probability that they would arrive on time using personal vehicles is much higher than using the metro public transportation system (MPTS)
B: The probability that they would arrive on time using the MPTS is much higher than using their personal vehicles Correct answer
C: The two probabilities are about the same excepting in one case the consistency is higher than the other
D: We need to compile more data around weekends to incorporate for traffic differences
E: When Standard Deviation is higher the probability goes down and so the MPTS is worse
Correct Answer:
B. The probability that they would arrive on time using the MPTS is much higher than using their personal vehicles
Explanation

To determine the probability of arriving on time (in 40 minutes or less), we calculate the Z-score for each transportation method, assuming a normal distribution. The Z-score measures how many standard deviations an element is from the mean.
1. Personal Vehicle: Mean (μ) = 39 min, Standard Deviation (σ) = 7 min, Target (X) = 40 min. Z = (X - μ) / σ = (40 - 39) / 7 ≈ 0.143. The probability P(Z ≤ 0.143) is approximately 55.7%.
2. Metro Public Transportation System (MPTS): Mean (μ) = 34 min, Standard Deviation (σ) = 21 min, Target (X) = 40 min. Z = (X - μ) / σ = (40 - 34) / 21 ≈ 0.286. The probability P(Z ≤ 0.286) is approximately 61.3%. Since 61.3% > 55.7%, the probability of arriving on time is higher using the MPTS.

Why Incorrect

A. The probability for personal vehicles (≈56%) is lower, not higher, than for the MPTS (≈61%).
C. The probabilities are demonstrably different (55.7% vs. 61.3%) and therefore not "about the same."
D. The problem is explicitly about the "average weekday commute," making weekend data irrelevant to the analysis.
E. This statement is a flawed generalization. While the MPTS has a higher standard deviation, its mean is significantly lower, which results in a higher probability of meeting the 40-minute target.

References

1. Montgomery, D. C. (2013). Introduction to statistical quality control (7th ed.). Wiley. Section 4.3, "The Normal Distribution," explains the use of the standard normal distribution and the Z-score transformation, Z = (X - μ) / σ, to compute probabilities for any normally distributed random variable (pp. 122-125).

2. The Pennsylvania State University. (n.d.). STAT 500: Applied Statistics, Lesson 4: Normal Distribution. Eberly College of Science. Retrieved from https://online.stat.psu.edu/stat500/lesson/4. This courseware details the process of "Standardization" (calculating a Z-score) to find the probability of a value falling within a certain range for any normal distribution.

3. Pyzdek, T., & Keller, P. A. (2018). The Six Sigma handbook (5th ed.). McGraw-Hill Education. Chapter 13, "Basic Control Charts," discusses how the normal distribution is fundamental to understanding process variation and capability, which involves calculating the probability of meeting specifications (pp. 265-267).

Scroll to Top