CSSBB practice question 11 of 25

The median is a better choice than the mean for a measure of central tendency if the data:

Full set: 188 questions
Answer options
A: is bimodal
B: often has outliers Correct answer
C: is normally distributed
D: is exponentially distributed
Correct Answer:
B. often has outliers
Explanation

The median is a robust estimator of location whose value is unaffected by the magnitude of extreme observations; it has a 50 % breakdown point, whereas the mean’s breakdown point is 0 %. Therefore, when a data set is prone to outliers, the median provides a truer indication of the “typical” value than the mean, which can be pulled arbitrarily far by a single extreme value. For distributions without substantial contamination, either statistic is acceptable, but under frequent or severe outliers the median is clearly preferred.

Why Incorrect

A. Bimodal data have two peaks; neither mean nor median represents either mode well—median is not conspicuously superior.
C. In a normal distribution the mean is unbiased and efficient; mean = median, so median offers no advantage.
D. Exponential distributions are skewed but rarely contain extreme contamination; both statistics are sensitive to skew, but outlier-robustness (the issue asked) is not the primary concern.

References

1. Wilcox

R.R. “Introduction to Robust Estimation and Hypothesis Testing

” 3rd ed.

Academic Press

2012

pp. 4-5 (median’s robustness and breakdown point).

2. Huber

P.J. & Ronchetti

E. “Robust Statistics

” 2nd ed.

Wiley

2009

Sect. 2.1

pp. 8-10 (median vs. mean under outliers).

3. MIT OpenCourseWare

6.041/6.431 “Statistics for Applications

” Lecture 1 notes

slides 16-18 (discussion of mean’s sensitivity to outliers

median’s resistance).

4. Casella

G. & Berger

R.L. “Statistical Inference

” 2nd ed.

Cengage

2002

Example 1.5 (effect of a single extreme observation on mean vs. median).

5. University of Wisconsin-Madison

STAT 471 Course Pack

Chap. 1

pp. 12-13 (choice of median for outlier-prone data).

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